Using the Zero to Factor the Polynomial

Oct 13, 2025 by magicalceylontours.com 110 views

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Introduction

In algebra, factorization is a crucial concept that helps us simplify complex expressions and equations. When dealing with polynomials, factorization can be a challenging task, especially when the polynomial is cubic. In this article, we will explore the factorization of a given cubic polynomial, $f(x) = 20x^3 + 39x^2 - 3x - 2$ , with the additional information that $\frac{1}{4}$ is a zero.

Understanding the Problem

The given polynomial is a cubic polynomial, meaning it has a degree of 3. This implies that it can be factored into the product of three binomials. However, the presence of a zero, $\frac{1}{4}$ , provides us with valuable information that can aid in the factorization process.

Using the Zero to Factor the Polynomial

When we know that $\frac{1}{4}$ is a zero of the polynomial, we can use this information to write the polynomial as a product of two binomials. The first binomial will be of the form $(x - \frac{1}{4})$ , where $\frac{1}{4}$ is the zero. The second binomial will be a quadratic expression that we need to determine.

Finding the Quadratic Factor

To find the quadratic factor, we can use polynomial division or synthetic division. However, in this case, we can also use the fact that the polynomial is a cubic polynomial and that we know one of its zeros. We can write the polynomial as:

f(x) = (x - \frac{1}{4})(ax^2 + bx + c)

where $a$ , $b$ , and $c$ are constants that we need to determine.

Determining the Coefficients

To determine the coefficients $a$ , $b$ , and $c$ , we can expand the product $(x - \frac{1}{4})(ax^2 + bx + c)$ and equate the resulting expression with the original polynomial $f(x) = 20x^3 + 39x^2 - 3x - 2$ . This will give us a system of equations that we can solve to find the values of $a$ , $b$ , and $c$ .

Solving the System of Equations

Expanding the product $(x - \frac{1}{4})(ax^2 + bx + c)$ , we get:

f(x) = ax^3 - \frac{1}{4}ax^2 + bx^2 - \frac{1}{4}bx + cx - \frac{1}{4}c

Equating this expression with the original polynomial $f(x) = 20x^3 + 39x^2 - 3x - 2$ , we get:

ax^3 - \frac{1}{4}ax^2 + bx^2 - \frac{1}{4}bx + cx - \frac{1}{4}c = 20x^3 + 39x^2 - 3x - 2

Comparing the coefficients of the corresponding terms, we get the following system of equations:

a = 20

-\frac{1}{4}a + b = 39

-\frac{1}{4}b + c = -3

-\frac{1}{4}c = -2

Solving for the Coefficients

Solving the system of equations, we get:

a = 20

b = 52

c = -13

Factoring the Polynomial

Now that we have determined the coefficients $a$ , $b$ , and $c$ , we can write the polynomial as:

f(x) = (x - \frac{1}{4})(20x^2 + 52x - 13)

Conclusion

In this article, we have factorized a given cubic polynomial, $f(x) = 20x^3 + 39x^2 - 3x - 2$ , with the additional information that $\frac{1}{4}$ is a zero. We have used the zero to write the polynomial as a product of two binomials and have determined the coefficients of the quadratic factor using polynomial division or synthetic division. The final factorization of the polynomial is $(x - \frac{1}{4})(20x^2 + 52x - 13)$ .

Final Answer

The final answer is $\boxed{(x - \frac{1}{4})(20x^2 + 52x - 13)}$ .

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Introduction

In our previous article, we explored the factorization of a given cubic polynomial, $f(x) = 20x^3 + 39x^2 - 3x - 2$ , with the additional information that $\frac{1}{4}$ is a zero. In this article, we will answer some frequently asked questions related to the factorization of cubic polynomials.

Q: What is the significance of knowing a zero of a polynomial?

A: Knowing a zero of a polynomial is crucial in factorizing the polynomial. It allows us to write the polynomial as a product of two binomials, one of which is of the form $(x - \text{zero})$ . This makes it easier to determine the other factor.

Q: How do I find the other factor of a polynomial if I know one of its zeros?

A: To find the other factor, you can use polynomial division or synthetic division. Alternatively, you can use the fact that the polynomial is a cubic polynomial and that you know one of its zeros. You can write the polynomial as $(x - \text{zero})(ax^2 + bx + c)$ and determine the coefficients $a$ , $b$ , and $c$ using the original polynomial.

Q: What is the difference between polynomial division and synthetic division?

A: Polynomial division and synthetic division are both methods used to divide a polynomial by another polynomial or a linear expression. The main difference between the two methods is that polynomial division is a more general method that can be used to divide polynomials of any degree, while synthetic division is a faster and more efficient method that is specifically designed for dividing polynomials by linear expressions.

Q: How do I determine the coefficients of the quadratic factor?

A: To determine the coefficients of the quadratic factor, you can use the original polynomial and the fact that the polynomial is a cubic polynomial. You can write the polynomial as $(x - \text{zero})(ax^2 + bx + c)$ and determine the coefficients $a$ , $b$ , and $c$ using the original polynomial.

Q: What is the final factorization of the polynomial?

A: The final factorization of the polynomial is $(x - \frac{1}{4})(20x^2 + 52x - 13)$ .

Q: Can I use the same method to factorize other polynomials?

A: Yes, you can use the same method to factorize other polynomials. However, you need to make sure that you have enough information about the polynomial, such as its zeros or other factors.

Q: What are some common mistakes to avoid when factorizing polynomials?

A: Some common mistakes to avoid when factorizing polynomials include:

Not using enough information about the polynomial
Not checking the factorization for errors
Not using the correct method for factorizing the polynomial
Not simplifying the factorization

Conclusion

In this article, we have answered some frequently asked questions related to the factorization of cubic polynomials. We have discussed the significance of knowing a zero of a polynomial, how to find the other factor, and how to determine the coefficients of the quadratic factor. We have also provided some common mistakes to avoid when factorizing polynomials.

Final Answer

The final answer is $\boxed{(x - \frac{1}{4})(20x^2 + 52x - 13)}$ .