The Reaction Between Barium Hydroxide and Sulfuric Acid

Oct 13, 2025 by magicalceylontours.com 85 views

Introduction

In this article, we will explore the reaction that occurs when a solution of barium hydroxide ($$Ba(OH)_2$$) is added to aqueous sulfuric acid ($$H_2SO_4$$). We will write the balanced chemical equation for this reaction, including state symbols, and discuss why the enthalpy change of neutralization cannot be determined using the addition of dilute sulfuric acid.

The Reaction Between Barium Hydroxide and Sulfuric Acid

When a solution of barium hydroxide is added to aqueous sulfuric acid, a neutralization reaction occurs. The barium hydroxide reacts with the sulfuric acid to form barium sulfate ($$BaSO_4$$), water ($$H_2O$$), and hydrogen gas ($$H_2$$).

The balanced chemical equation for this reaction is:

Ba(OH)_2(aq) + H_2SO_4(aq) \rightarrow BaSO_4(s) + 2H_2O(l) + H_2(g)

State Symbols

In the above equation, the state symbols are used to indicate the physical state of each substance. The symbols used are:

$(aq)$$: aqueous solution (liquid)$
$(s)$$: solid$
$(l)$$: liquid$
$Ba(OH)_2(aq) + H_2SO_4(aq) \rightarrow BaSO_4(s) + 2H_2O(l) + H_2(g)$

Q: What is the role of state symbols in the balanced chemical equation?

A: State symbols are used to indicate the physical state of each substance in the balanced chemical equation. In this case, the state symbols used are:
- $(aq)$$: aqueous solution (liquid)$
- $(s)$$: solid$
- $(l)$$: liquid$
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