Finding the Reciprocals of the Roots

Oct 13, 2025 by magicalceylontours.com 69 views

===========================================================

Introduction

In algebra, a quadratic polynomial is a polynomial of degree two, which means the highest power of the variable is two. The general form of a quadratic polynomial is ${f(x) = ax^2 + bx + c}$ , where ${a}$ , ${b}$ , and ${c}$ are constants, and ${a}$ cannot be zero. In this article, we will focus on finding the sum of the reciprocals of the roots of a quadratic polynomial.

Understanding the Problem

The problem states that ${\alpha}$ and ${\beta}$ are the zeroes of the polynomial ${f(x) = x^2 + x - 1}$ . This means that when we substitute ${\alpha}$ and ${\beta}$ into the polynomial, we get zero. In other words, ${\alpha}$ and ${\beta}$ are the solutions to the equation ${x^2 + x - 1 = 0}$ .

Reciprocals of the Roots

The problem asks us to find the sum of the reciprocals of the roots, which is ${\frac{1}{\alpha} + \frac{1}{\beta}}$ . To find this sum, we need to first find the reciprocals of the roots.

Finding the Reciprocals of the Roots

To find the reciprocals of the roots, we can use the fact that if ${\alpha}$ and ${\beta}$ are the roots of the polynomial, then ${\frac{1}{\alpha}}$ and ${\frac{1}{\beta}}$ are the roots of the polynomial ${\frac{1}{x^2 + x - 1}}$ .

Simplifying the Polynomial

To simplify the polynomial, we can multiply both the numerator and the denominator by the conjugate of the denominator. The conjugate of ${x^2 + x - 1}$ is ${x^2 - x - 1}$ .

Multiplying the Polynomial

Multiplying the polynomial, we get:

${\frac{1}{x^2 + x - 1} = \frac{x^2 - x - 1}{(x^2 + x - 1)(x^2 - x - 1)}}$

Simplifying the Denominator

Simplifying the denominator, we get:

${(x^2 + x - 1)(x^2 - x - 1) = x^4 - x^2 - x^3 + x^2 + x^2 - x - x^2 + x + 1}$

Combining Like Terms

Combining like terms, we get:

${x^4 - x^3 + 1}$

Finding the Roots of the Polynomial

To find the roots of the polynomial, we can use the quadratic formula:

${x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}}$

Applying the Quadratic Formula

Applying the quadratic formula, we get:

${x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4(1)(1)}}{2(1)}}$

Simplifying the Expression

Simplifying the expression, we get:

${x = \frac{1 \pm \sqrt{-3}}{2}}$

Finding the Reciprocals of the Roots

Simplifying the Polynomial

To simplify the polynomial, we can multiply both the numerator and the denominator by the conjugate of the denominator. The conjugate of ${x^2 - x - 1}$ is ${x^2 + x - 1}$ .

Multiplying the Polynomial

Multiplying the polynomial, we get:

${\frac{1}{x^2 - x - 1} = \frac{x^2 + x - 1}{(x^2 - x - 1)(x^2 + x - 1)}}$

Simplifying the Denominator

Simplifying the denominator, we get:

${(x^2 - x - 1)(x^2 + x - 1) = x^4 + x^2 - x^3 - x^2 - x^2 - x + x^2 + x + 1}$

Combining Like Terms

Combining like terms, we get:

${x^4 - x^3 + 1}$

Finding the Sum of the Reciprocals of the Roots

To find the sum of the reciprocals of the roots, we can use the fact that if ${\alpha}$ and ${\beta}$ are the roots of the polynomial, then ${\frac{1}{\alpha} + \frac{1}{\beta}}$ is equal to the negative of the coefficient of the linear term divided by the constant term.

Finding the Coefficient of the Linear Term

The coefficient of the linear term is -1.

Finding the Constant Term

The constant term is 1.

Finding the Sum of the Reciprocals of the Roots

The sum of the reciprocals of the roots is equal to the negative of the coefficient of the linear term divided by the constant term, which is:

${\frac{-(-1)}{1} = 1}$

Conclusion

In conclusion, the sum of the reciprocals of the roots of the polynomial ${f(x) = x^2 + x - 1}$ is 1.

Final Answer

The final answer is 1.

=====================================================================================================

Q: What is a quadratic polynomial?

A: A quadratic polynomial is a polynomial of degree two, which means the highest power of the variable is two. The general form of a quadratic polynomial is ${f(x) = ax^2 + bx + c}$ , where ${a}$ , ${b}$ , and ${c}$ are constants, and ${a}$ cannot be zero.

Q: How do I find the sum of the reciprocals of the roots of a quadratic polynomial?

A: To find the sum of the reciprocals of the roots of a quadratic polynomial, you can use the fact that if ${\alpha}$ and ${\beta}$ are the roots of the polynomial, then ${\frac{1}{\alpha} + \frac{1}{\beta}}$ is equal to the negative of the coefficient of the linear term divided by the constant term.

Q: What is the coefficient of the linear term in a quadratic polynomial?

A: The coefficient of the linear term in a quadratic polynomial is the coefficient of the ${x}$ term, which is ${b}$ .

Q: What is the constant term in a quadratic polynomial?

A: The constant term in a quadratic polynomial is the term that is not multiplied by any variable, which is ${c}$ .

Q: How do I find the sum of the reciprocals of the roots of a quadratic polynomial with complex roots?

A: To find the sum of the reciprocals of the roots of a quadratic polynomial with complex roots, you can use the fact that if ${\alpha}$ and ${\beta}$ are the complex roots of the polynomial, then ${\frac{1}{\alpha} + \frac{1}{\beta}}$ is equal to the negative of the coefficient of the linear term divided by the constant term.

Q: Can I use the quadratic formula to find the roots of a quadratic polynomial?

A: Yes, you can use the quadratic formula to find the roots of a quadratic polynomial. The quadratic formula is:

${x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}}$

Q: What is the quadratic formula?

A: The quadratic formula is a formula that is used to find the roots of a quadratic polynomial. It is:

${x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}}$

Q: How do I apply the quadratic formula to find the roots of a quadratic polynomial?

A: To apply the quadratic formula, you need to plug in the values of ${a}$ , ${b}$ , and ${c}$ into the formula and simplify.

Q: Can I use the quadratic formula to find the sum of the reciprocals of the roots of a quadratic polynomial?

A: No, you cannot use the quadratic formula to find the sum of the reciprocals of the roots of a quadratic polynomial. Instead, you can use the fact that if ${\alpha}$ and ${\beta}$ are the roots of the polynomial, then ${\frac{1}{\alpha} + \frac{1}{\beta}}$ is equal to the negative of the coefficient of the linear term divided by the constant term.

Q: What is the sum of the reciprocals of the roots of the polynomial ${f(x) = x^2 + x - 1}$ ?

A: The sum of the reciprocals of the roots of the polynomial ${f(x) = x^2 + x - 1}$ is 1.

Q: Can I use the quadratic formula to find the roots of a quadratic polynomial with complex roots?

A: Yes, you can use the quadratic formula to find the roots of a quadratic polynomial with complex roots. However, you need to be careful when simplifying the expression, as it may involve complex numbers.

Q: What is the difference between a quadratic polynomial and a quadratic equation?

A: A quadratic polynomial is a polynomial of degree two, while a quadratic equation is an equation of the form ${ax^2 + bx + c = 0}$ .