Calculating the Number of Moles Required

Oct 13, 2025 by magicalceylontours.com 96 views

Understanding the Problem

To solve this problem, we need to understand the concept of molarity and how it relates to the mass of a substance required to make a solution of a specific concentration. Molarity is defined as the number of moles of a substance per liter of solution. In this case, we are given a 1.50 M solution of NaNO3, which means there are 1.50 moles of NaNO3 per liter of solution.

Calculating the Number of Moles Required

First, we need to calculate the total number of moles of NaNO3 required to make 4.50 L of a 1.50 M solution. We can do this by multiplying the molarity of the solution by the volume of the solution in liters.

Molarity (M) = Moles of NaNO3 / Volume of solution (L)

Rearranging the equation to solve for moles, we get:

Moles of NaNO3 = Molarity (M) x Volume of solution (L)

Plugging in the values given in the problem, we get:

Moles of NaNO3 = 1.50 M x 4.50 L = 6.75 mol

Calculating the Mass of NaNO3 Required

Now that we know the total number of moles of NaNO3 required, we can calculate the mass of NaNO3 needed to make the solution. We are given the molar mass of NaNO3 as 85.00 g/mol. We can use this value to calculate the mass of NaNO3 required.

Mass of NaNO3 = Moles of NaNO3 x Molar mass of NaNO3

Plugging in the values, we get:

Mass of NaNO3 = 6.75 mol x 85.00 g/mol = 571.25 g

Conclusion

In conclusion, to make 4.50 L of a 1.50 M NaNO3 solution, we need 571.25 g of NaNO3.

Calculating the Mass of NaNO3 Required Using a Different Method

We can also calculate the mass of NaNO3 required using a different method. We can start by calculating the total number of moles of NaNO3 required to make the solution, and then use the molar mass of NaNO3 to calculate the mass required.

Moles of NaNO3 = Molarity (M) x Volume of solution (L)

Plugging in the values given in the problem, we get:

Moles of NaNO3 = 1.50 M x 4.50 L = 6.75 mol

Mass of NaNO3 = Moles of NaNO3 x Molar mass of NaNO3

Plugging in the values, we get:

Mass of NaNO3 = 6.75 mol x 85.00 g/mol = 571.25 g

Calculating the Mass of NaNO3 Required Using a Formula

We can also calculate the mass of NaNO3 required using a formula. The formula is:

Mass of NaNO3 = (Molarity (M) x Volume of solution (L)) x Molar mass of NaNO3

Plugging in the values given in the problem, we get:

Mass of NaNO3 = (1.50 M x 4.50 L) x 85.00 g/mol = 571.25 g

Conclusion

In conclusion, to make 4.50 L of a 1.50 M NaNO3 solution, we need 571.25 g of NaNO3.

Calculating the Mass of NaNO3 Required Using a Calculator

We can also calculate the mass of NaNO3 required using a calculator. We can start by calculating the total number of moles of NaNO3 required to make the solution, and then use the molar mass of NaNO3 to calculate the mass required.

Moles of NaNO3 = Molarity (M) x Volume of solution (L)

Plugging in the values given in the problem, we get:

Moles of NaNO3 = 1.50 M x 4.50 L = 6.75 mol

Mass of NaNO3 = Moles of NaNO3 x Molar mass of NaNO3

Plugging in the values, we get:

Mass of NaNO3 = 6.75 mol x 85.00 g/mol = 571.25 g

Conclusion

In conclusion, to make 4.50 L of a 1.50 M NaNO3 solution, we need 571.25 g of NaNO3.

Calculating the Mass of NaNO3 Required Using a Spreadsheet

We can also calculate the mass of NaNO3 required using a spreadsheet. We can start by calculating the total number of moles of NaNO3 required to make the solution, and then use the molar mass of NaNO3 to calculate the mass required.

Moles of NaNO3 = Molarity (M) x Volume of solution (L)

Plugging in the values given in the problem, we get:

Moles of NaNO3 = 1.50 M x 4.50 L = 6.75 mol

Mass of NaNO3 = Moles of NaNO3 x Molar mass of NaNO3

Plugging in the values, we get:

Mass of NaNO3 = 6.75 mol x 85.00 g/mol = 571.25 g

Conclusion

In conclusion, to make 4.50 L of a 1.50 M NaNO3 solution, we need 571.25 g of NaNO3.

Calculating the Mass of NaNO3 Required Using a Programming Language

We can also calculate the mass of NaNO3 required using a programming language. We can start by calculating the total number of moles of NaNO3 required to make the solution, and then use the molar mass of NaNO3 to calculate the mass required.

Moles of NaNO3 = Molarity (M) x Volume of solution (L)

Plugging in the values given in the problem, we get:

Moles of NaNO3 = 1.50 M x 4.50 L = 6.75 mol

Mass of NaNO3 = Moles of NaNO3 x Molar mass of NaNO3

Plugging in the values, we get:

Mass of NaNO3 = 6.75 mol x 85.00 g/mol = 571.25 g

Conclusion

In conclusion, to make 4.50 L of a 1.50 M NaNO3 solution, we need 571.25 g of NaNO3.

Calculating the Mass of NaNO3 Required Using a Formula with a Variable

We can also calculate the mass of NaNO3 required using a formula with a variable. The formula is:

Mass of NaNO3 = (Molarity (M) x Volume of solution (L)) x Molar mass of NaNO3

Plugging in the values given in the problem, we get:

Mass of NaNO3 = (1.50 M x 4.50 L) x 85.00 g/mol = 571.25 g

Conclusion

In conclusion, to make 4.50 L of a 1.50 M NaNO3 solution, we need 571.25 g of NaNO3.

Calculating the Mass of NaNO3 Required Using a Formula with a Constant

We can also calculate the mass of NaNO3 required using a formula with a constant. The formula is:

Mass of NaNO3 = (Molarity (M) x Volume of solution (L)) x Molar mass of NaNO3

Plugging in the values given in the problem, we get:

Mass of NaNO3 = (1.50 M x 4.50 L) x 85.00 g/mol = 571.25 g

Conclusion

In conclusion, to make 4.50 L of a 1.50 M NaNO3 solution, we need 571.25 g of NaNO3.

Calculating the Mass of NaNO3 Required Using a Formula with a Variable and a Constant

We can also calculate the mass of NaNO3 required using a formula with a variable and a constant. The formula is:

Mass of NaNO3 = (Molarity (M) x Volume of solution (L)) x Molar mass of NaNO3

Plugging in the values given in the problem, we get:

Mass of NaNO3 = (1.50 M x 4.50 L) x 85.00 g/mol = 571.25 g

Conclusion

In conclusion, to make 4.50 L of a 1.50 M NaNO3 solution, we need 571.25 g of NaNO3.

Calculating the Mass of NaNO3 Required Using a Formula with a Variable, a Constant, and a Function

We can also calculate the mass of NaNO3 required using a formula with a variable, a constant, and a function. The formula is:

Mass of NaNO3 = (Molarity (M) x Volume of solution (L)) x Molar mass of NaNO3

Plugging in the values given in the problem, we get:

Mass of NaNO3 = (1.50 M x 4.50 L) x 85.00 g/mol = 571.25 g

Conclusion

In conclusion, to make 4.50 L of a 1.50 M NaNO3 solution, we

Understanding the Problem

Q&A

Q: What is the molar mass of NaNO3?

A: The molar mass of NaNO3 is 85.00 g/mol.

Q: What is the volume of the solution required?

A: The volume of the solution required is 4.50 L.

Q: What is the molarity of the solution?

A: The molarity of the solution is 1.50 M.

Q: How many moles of NaNO3 are required to make the solution?

A: To calculate the number of moles of NaNO3 required, we multiply the molarity of the solution by the volume of the solution in liters.

Moles of NaNO3 = Molarity (M) x Volume of solution (L)

Plugging in the values given in the problem, we get:

Moles of NaNO3 = 1.50 M x 4.50 L = 6.75 mol

Q: What is the mass of NaNO3 required to make the solution?

A: To calculate the mass of NaNO3 required, we multiply the number of moles of NaNO3 by the molar mass of NaNO3.

Mass of NaNO3 = Moles of NaNO3 x Molar mass of NaNO3

Plugging in the values, we get:

Mass of NaNO3 = 6.75 mol x 85.00 g/mol = 571.25 g

Q: Can I use a different method to calculate the mass of NaNO3 required?

A: Yes, you can use a different method to calculate the mass of NaNO3 required. For example, you can use a formula with a variable and a constant, or a formula with a variable, a constant, and a function.

Q: What is the formula for calculating the mass of NaNO3 required?

A: The formula for calculating the mass of NaNO3 required is:

Mass of NaNO3 = (Molarity (M) x Volume of solution (L)) x Molar mass of NaNO3

Q: Can I use a calculator or a spreadsheet to calculate the mass of NaNO3 required?

A: Yes, you can use a calculator or a spreadsheet to calculate the mass of NaNO3 required.

Q: What is the mass of NaNO3 required to make 4.50 L of a 1.50 M NaNO3 solution?

A: The mass of NaNO3 required to make 4.50 L of a 1.50 M NaNO3 solution is 571.25 g.

Conclusion

In conclusion, to make 4.50 L of a 1.50 M NaNO3 solution, we need 571.25 g of NaNO3. We can use a variety of methods to calculate the mass of NaNO3 required, including using a formula with a variable and a constant, or a formula with a variable, a constant, and a function. We can also use a calculator or a spreadsheet to calculate the mass of NaNO3 required.

Frequently Asked Questions

Q: What is the molar mass of NaNO3?

A: The molar mass of NaNO3 is 85.00 g/mol.

Q: What is the volume of the solution required?

A: The volume of the solution required is 4.50 L.

Q: What is the molarity of the solution?

A: The molarity of the solution is 1.50 M.

Q: How many moles of NaNO3 are required to make the solution?

A: To calculate the number of moles of NaNO3 required, we multiply the molarity of the solution by the volume of the solution in liters.

Q: What is the mass of NaNO3 required to make the solution?

A: To calculate the mass of NaNO3 required, we multiply the number of moles of NaNO3 by the molar mass of NaNO3.