Calculating Moles of NH3 Produced

Oct 13, 2025 by magicalceylontours.com 10 views

Understanding the Chemical Reaction

The given chemical reaction is:

${ N_2 + 3 H_2 \rightarrow 2 NH_3 }$

This reaction involves the combination of nitrogen gas (N2) and hydrogen gas (H2) to produce ammonia (NH3). The reaction is a classic example of a synthesis reaction, where two or more substances combine to form a new compound.

Calculating Moles of NH3 Produced

To calculate the moles of NH3 produced from the given reaction, we need to use the mole ratio between N2 and NH3. From the balanced equation, we can see that 1 mole of N2 produces 2 moles of NH3.

Calculating Moles of NH3 Produced from 5 mol N2

Given that we start with 5 mol of N2, we can calculate the moles of NH3 produced as follows:

${ 5 \, \text{mol} \, N_2 \times \frac{2 \, \text{mol} \, NH_3}{1 \, \text{mol} \, N_2} = 10 \, \text{mol} \, NH_3 }$

Therefore, 5 mol of N2 will produce 10 mol of NH3.

Calculating Moles of NH3 Produced from 10 mol N2

To calculate the moles of NH3 produced from 10 mol of N2, we can simply multiply the number of moles of N2 by the mole ratio:

${ 10 \, \text{mol} \, N_2 \times \frac{2 \, \text{mol} \, NH_3}{1 \, \text{mol} \, N_2} = 20 \, \text{mol} \, NH_3 }$

Therefore, 10 mol of N2 will produce 20 mol of NH3.

Calculating Moles of NH3 Produced from 15 mol N2

To calculate the moles of NH3 produced from 15 mol of N2, we can simply multiply the number of moles of N2 by the mole ratio:

${ 15 \, \text{mol} \, N_2 \times \frac{2 \, \text{mol} \, NH_3}{1 \, \text{mol} \, N_2} = 30 \, \text{mol} \, NH_3 }$

Therefore, 15 mol of N2 will produce 30 mol of NH3.

Calculating Moles of NH3 Produced from 20 mol N2

To calculate the moles of NH3 produced from 20 mol of N2, we can simply multiply the number of moles of N2 by the mole ratio:

${ 20 \, \text{mol} \, N_2 \times \frac{2 \, \text{mol} \, NH_3}{1 \, \text{mol} \, N_2} = 40 \, \text{mol} \, NH_3 }$

Therefore, 20 mol of N2 will produce 40 mol of NH3.

Calculating Moles of NH3 Produced from 25 mol N2

To calculate the moles of NH3 produced from 25 mol of N2, we can simply multiply the number of moles of N2 by the mole ratio:

${ 25 \, \text{mol} \, N_2 \times \frac{2 \, \text{mol} \, NH_3}{1 \, \text{mol} \, N_2} = 50 \, \text{mol} \, NH_3 }$

Therefore, 25 mol of N2 will produce 50 mol of NH3.

Calculating Moles of NH3 Produced from 30 mol N2

To calculate the moles of NH3 produced from 30 mol of N2, we can simply multiply the number of moles of N2 by the mole ratio:

${ 30 \, \text{mol} \, N_2 \times \frac{2 \, \text{mol} \, NH_3}{1 \, \text{mol} \, N_2} = 60 \, \text{mol} \, NH_3 }$

Therefore, 30 mol of N2 will produce 60 mol of NH3.

Calculating Moles of NH3 Produced from 35 mol N2

To calculate the moles of NH3 produced from 35 mol of N2, we can simply multiply the number of moles of N2 by the mole ratio:

${ 35 \, \text{mol} \, N_2 \times \frac{2 \, \text{mol} \, NH_3}{1 \, \text{mol} \, N_2} = 70 \, \text{mol} \, NH_3 }$

Therefore, 35 mol of N2 will produce 70 mol of NH3.

Calculating Moles of NH3 Produced from 40 mol N2

To calculate the moles of NH3 produced from 40 mol of N2, we can simply multiply the number of moles of N2 by the mole ratio:

${ 40 \, \text{mol} \, N_2 \times \frac{2 \, \text{mol} \, NH_3}{1 \, \text{mol} \, N_2} = 80 \, \text{mol} \, NH_3 }$

Therefore, 40 mol of N2 will produce 80 mol of NH3.

Calculating Moles of NH3 Produced from 45 mol N2

To calculate the moles of NH3 produced from 45 mol of N2, we can simply multiply the number of moles of N2 by the mole ratio:

${ 45 \, \text{mol} \, N_2 \times \frac{2 \, \text{mol} \, NH_3}{1 \, \text{mol} \, N_2} = 90 \, \text{mol} \, NH_3 }$

Therefore, 45 mol of N2 will produce 90 mol of NH3.

Calculating Moles of NH3 Produced from 50 mol N2

To calculate the moles of NH3 produced from 50 mol of N2, we can simply multiply the number of moles of N2 by the mole ratio:

${ 50 \, \text{mol} \, N_2 \times \frac{2 \, \text{mol} \, NH_3}{1 \, \text{mol} \, N_2} = 100 \, \text{mol} \, NH_3 }$

Therefore, 50 mol of N2 will produce 100 mol of NH3.

Conclusion

In conclusion, we have calculated the moles of NH3 produced from different amounts of N2 using the mole ratio from the balanced equation. The results show that the moles of NH3 produced are directly proportional to the moles of N2 used. This demonstrates the importance of understanding the mole ratio in chemical reactions and how it can be used to calculate the amount of product produced.

References

Chemical Equation Balancing: A tutorial on balancing chemical equations.
Mole Ratio: A tutorial on mole ratio and its importance in chemical reactions.
Chemical Reactions: A tutorial on chemical reactions and their types.

Q: What is the mole ratio between N2 and NH3 in the given chemical reaction?

A: The mole ratio between N2 and NH3 in the given chemical reaction is 1:2. This means that 1 mole of N2 produces 2 moles of NH3.

Q: How can I calculate the moles of NH3 produced from a given amount of N2?

A: To calculate the moles of NH3 produced from a given amount of N2, you can use the mole ratio from the balanced equation. Simply multiply the number of moles of N2 by the mole ratio (2:1).

Q: What is the importance of understanding the mole ratio in chemical reactions?

A: Understanding the mole ratio in chemical reactions is crucial because it allows you to calculate the amount of product produced from a given amount of reactant. This is essential in chemistry and is used in a wide range of applications, from industrial processes to laboratory experiments.

Q: Can I use the mole ratio to calculate the moles of N2 required to produce a given amount of NH3?

A: Yes, you can use the mole ratio to calculate the moles of N2 required to produce a given amount of NH3. Simply multiply the number of moles of NH3 by the mole ratio (1:2).

Q: What is the relationship between the moles of N2 and the moles of NH3 produced in the given chemical reaction?

A: The moles of N2 and the moles of NH3 produced in the given chemical reaction are directly proportional. This means that the more moles of N2 used, the more moles of NH3 produced.

Q: Can I use the mole ratio to calculate the percentage yield of NH3 produced from a given amount of N2?

A: Yes, you can use the mole ratio to calculate the percentage yield of NH3 produced from a given amount of N2. Simply calculate the moles of NH3 produced and divide it by the theoretical yield (calculated using the mole ratio).

Q: What are some common applications of the mole ratio in chemistry?

A: The mole ratio is used in a wide range of applications, including:

Calculating the amount of product produced from a given amount of reactant
Determining the limiting reactant in a chemical reaction
Calculating the percentage yield of a product
Understanding the stoichiometry of a chemical reaction

Q: Can I use the mole ratio to calculate the moles of other products produced in a chemical reaction?

A: Yes, you can use the mole ratio to calculate the moles of other products produced in a chemical reaction. Simply multiply the number of moles of the reactant by the mole ratio for each product.

Q: What are some common mistakes to avoid when using the mole ratio in chemistry?

A: Some common mistakes to avoid when using the mole ratio in chemistry include:

Not balancing the chemical equation
Not understanding the mole ratio
Not using the correct units
Not calculating the theoretical yield

Conclusion

In conclusion, the mole ratio is a fundamental concept in chemistry that is used to calculate the amount of product produced from a given amount of reactant. Understanding the mole ratio is essential in chemistry and is used in a wide range of applications. By following the steps outlined in this article, you can use the mole ratio to calculate the moles of NH3 produced from a given amount of N2.

References

Chemical Equation Balancing: A tutorial on balancing chemical equations.
Mole Ratio: A tutorial on mole ratio and its importance in chemical reactions.
Chemical Reactions: A tutorial on chemical reactions and their types.